Chapter 4 Physics of
Matter
Vacuum
|
|
|
A vacuum exists in outer space. |
|
It is the absence of all matter. |
|
Vacuums are relative |
|
Even in outer space some matter exists |
|
But the amount is so small that a
person would die if exposed to vacuum without a space suite |
States of Matter
Solid
|
|
|
Solid A rigid body, retains its shape unless distorted by a strong
force.. Examples: rock, wood,
plastic, iron |
Liquid
|
|
|
Flow readily, |
|
conform to the shape of their
container. |
|
Have a well defined boundary (surface). |
|
More dense than gases. |
|
Examples water, beverages, blood, oil,… |
Gas
|
|
|
Flow readily, |
|
conform to the shape and size of their
container, |
|
do not have a well defined surface, |
|
can be compressed or expanded readily. |
|
Examples: air, carbon dioxide, helium,
steam. |
Inside Liguid vs Gas
Plasma
|
|
|
An ionized gas, often referred to as
the fourth state of matter. |
|
It consists of positive ions and
electrons |
|
interacts strongly with magnetic fields |
|
conducts electricity. |
|
Commonly exists only at higher
temperatures or in strong electromagnetic fields |
|
Examples: Sun, candle flame, gases in
operating fluorescent, neon, and vapor lights. |
|
|
Structure or Particles of
Matter
|
|
|
|
Greeks described smallest particles of
matter as atoms. |
|
Now we know there are even smaller
particles. |
|
Atoms are composed of |
|
Electrons, protons and neutrons. |
|
Protons and neutrons are in the center
or nucleus of the atom |
|
Electrons orbit around the nucleus |
Neutrons, Protons,
Electrons
|
|
|
Neutron Electrically neutral particle
residing in the nucleus of an atom. |
|
Proton Positively charged particle
residing in the nucleus of an atom. |
|
Electron Negatively charged particle,
usually found orbiting the nucleus of an atom. |
|
|
Elements
|
|
|
One of over 115 different fundamental
substances |
|
The simplest and purest forms of
matter. |
|
All have the same type of Atom,
specifically the same number of protons in the nucleus. |
|
Scientists are still discovering new
elements so the number is always increasing. |
Examples of Elements
|
|
|
Gold, Silver, Oxygen, Silicon,
Nitrogen,…. |
|
Nitrogen is the most abundant element.
It makes up about 80% of our air. |
|
Silicon is also very abundant, since it
occurs in sand, a compound of Silicon and Oxygen. |
Molecule/Compound
|
|
|
Two or more atoms combine to form a
molecule. If the atoms are different
types
it is a compound. |
|
A Compound is something composed of
identical molecules of more than one type of atom or element. 2 or more elements combine chemically. |
|
E.G. SiO2 Is a compound
composed of molecules with Silicon and Oxygen atoms. |
|
|
Mixture
|
|
|
No chemical reaction, thus not a
compound |
|
Parts do not combine uniformly, they
just intermix. |
|
Parts can be recovered individually. |
|
Example, Instant Cocoa: chocolate,
sugar, and milk powder. |
Solutions
|
|
|
A homogeneous mixture of two or more
substances, which may be solids, liquids, gases, or a combination of these |
|
The parts break down into individual
molecules, and intersperse, but do not combine. |
|
E.G. salt in water-salt water |
|
|
Suspensions
|
|
|
A suspension has tiny particles, but
many molecules in one particle. |
|
Not a chemical reaction, thus not a
compound |
|
Their particles are larger than
molecules thus not a solution. |
Suspensions Examples
|
|
|
Mayonaise, Gelatin, Butter, Ice Cream
Orange Juice |
|
see http://encyclopedia.thefreedictionary.com/Suspension+(chemistry) |
Pressure (p)
|
|
|
The force per unit area for a force
acting perpendicular to a surface. The force acting on a surface divided by
its area. |
|
P = Force/Area = F/A |
|
Force on the floor= Weight = 100 lbs |
|
Area of shoes surface 30 sq.in. |
|
Pressure on the floor =100/30= 3.33psi |
|
|
Pressure from spike heels
|
|
|
Heel area = .2x.2in=.04sq.in |
|
Sole area =2 x 4 in = 8 sq.in. |
|
Weight=100 lbs. |
|
On Heel P=100/.04 =2500 psi |
|
On Sole P=100/8 = 12.5psi. |
Equal Forces Unequal P
|
|
|
Note force is the same in both cases
but the ratio of pressures is 2500/12.5 = 200 to 1! |
|
|
Mass density (D)
|
|
|
The mass per unit volume of a
substance. The mass of a quantity of a substance divided by the volume it
occupies. |
|
Mass density = mass/volume |
|
D=m/V = 20kg/2m3 = 10kg/m3 |
D of 2 x 2 x 4 m, 40KG
Cube
|
|
|
D=? |
|
M= 40 kg, |
|
Cube of dimensions 2 x 2 x 4 m. V=lwh = 2 x 2 x 4 = 16 cubic meters |
|
D = m/V = 40Kg/ 16 m3 = 2.5
kg/ m3 |
|
|
Weight density (Dw)
|
|
|
The weight per unit volume of a
substance. The weight of a quantity of a substance divided by the volume it
occupies. |
|
Dw = W/V = Weight/Volume |
|
= 196 N/2 cu.m =98 N/m3 |
Dw of 2 x 2 x
4 m, 40KG Cube
|
|
|
Dw =? |
|
M= 40 kg, W = 40 x 9.8 = 392 N |
|
Cube of dimensions 2 x 2 x 4 m. V=lwh = 2 x 2 x 4 = 16 cubic meters |
|
Dw = W/V = 392N/ 16 m3
= 24 N/ m3 |
|
|
Specific Gravity
|
|
|
Relation between density of a material
and density of water. |
|
Ratio Dx/Dw (Density of x divided by
density of water). |
What is the Specific
Gravity of Concrete?
|
|
|
Density of concrete =2500 kg/m3, |
|
Density of water = 1000 kg/m3. |
|
Specific Gravity of concrete = |
|
Dx/Dw = 2500/1000 |
|
= 2.5. Note, no units on sp.gr! |
Pressure in Fluids
|
|
|
Pressure increases with depth! |
|
Law of fluid pressure The (gauge)
pressure at any depth in a fluid at rest equals the weight of the fluid in a
column extending from that depth to the top of the fluid divided by the
cross-sectional area of the column. |
|
|
Law of fluid pressure
|
|
|
The (gauge) pressure at any depth in a
fluid at rest equals the weight of the fluid in a column extending from that
depth to the top of the fluid divided by the cross-sectional area of the
column. |
Pressure in Water
|
|
|
Water weighs 62.5 lbs/cu.ft |
|
A cube 1 x 1 x 1 ft has a surface of 1
sq.ft. |
|
At a depth of 1 ft you have 62.5
lbs/sqft pressure |
|
Multiply depth in ft by 62.5 to find P |
|
20 ft, P = 20 x 62.5 = 1250 lbs/sq.ft. |
Converting to lbs/sq.in
|
|
|
Gauges usually use lbs/sq.in |
|
1 sq.ft = 12in x 12 in = 144 sq.in. |
|
62.4 lbs/sq.ft = 62.4/144 |
|
= .433 lbs/sq.in. |
|
Thus using psi:p=0.433 psi/ft x h(ft) |
|
At 20 ft. P = .433 x 20 = 8.66 psi. |
Gauge pressure vs total p
|
|
|
measures difference between inside and
outside pressure? |
|
see p. 141 and 142 |
Buoyant force
|
|
|
The upward force exerted by a fluid on
a substance partly or completely immersed in it. |
Archimedes' Principle
|
|
|
The buoyant force acting on a substance
in a fluid at rest is equal to the weight of the fluid displaced by the
substance. |
|
|
Floating, Sinking, or
Rising
|
|
|
Buoyant force greater than weight of
object, object floats. |
|
Buoyant force less than weight, object
sinks. |
|
Light object released from a submarine
rises, if density less than water, otherwise sinks. |
|
|
Pascal's Principle
|
|
|
Pressure applied to an enclosed fluid
is transmitted undiminished to all parts of the fluid and to the walls of the
container. |
|
|
Problem Force from
Pressure and Area
|
|
|
Pressure = F/A then F = P x A |
|
Side of can 8 x 10 inches? |
|
Area 8 x 10 = 80 sq in., P=14.7psi |
|
F = 14.7 psi x 80 sq.in. = 1176 lbs |
|
|
Mass from Density Problem
|
|
|
Dm = M/Vol |
|
M = Dm x Vol |
|
Vol = 2m x 3m x 4m = 24 cu.m |
|
Dm = 11,340kg/cu.m |
|
M = 11,340 x 24 = 272,160 kg. |
|
|
Buoyant Force Problem
|
|
|
Swimmer’s volume = 2 ft3 |
|
Buoyant Force,BF = ? |
|
BF= Wt of water he displaces |
|
= His Vol x density of water (62.4
lbs/ft3) |
|
2 ft3 x 62.4 lbs/ft3
= 124.8 lbs |
|
|
Formulas Chapter 4
|
|
|
p= F/A
Pressure is Force divided by area perpendicular to the force |
|
Dm=m/V |
|
Mass density, Dm = mass,
m/volume, V |
|
Dw=w/V |
|
Weight Density, Dw = weight,
w/volume, V |
|
Fb= WFD |
|
Archimedes’ Principle: Buoyant Force =
Weight of the fluid displaced |
|
|
Special Case Equations
|
|
|
p=Dwh=Dm x g x
h Gauge Pressure, p at a depth h in a liquid of wt density Dw or
mass density Dm |
|
p=0.433 (psi/ft) x h(ft) Gauge
Pressure in psi underwater at a depth h in feet |
Navigation: Back To Web
|
|
|
Raymerry Home |
|
Back to Classes |
|
Back to Physics |